Scoring Scheme: 3-3-2-1 When you use the half reaction method to balance the redox reaction between one mole of NBS and ascorbic acid to give L-dehydroascorbic acid and succinimide, how many moles of electrons are transferred?

In the redox reaction between one mole of NBS and ascorbic acid, ascorbic acid undergoes oxidation reaction to form L-dehydroascorbic acid.

On other hand, N-bromosuccinimide (NBS) undergoes reduction to form succinimide.

Electron transferred during this process is two. Complete reaction is attached below for quick reference.

Thus, one molecule of NBS reacts with one molecule of ascorbic acid, during this redox reaction. For each molecule reacting, two electrons are transferred.

Thus, when one mole of NBS reacts with one mole of ascorbic acid, 2 x Na moles of electrons will be transferred. It may be noted here that, Na = Avagadro's number = 6.022 X 10^23.

aliasger2709 aliasger2709 · Answer 2 · 2022-06-06T13:00:44+02:00

The transfer of electrons between the chemical species is shown in the redox reaction. In the reaction, 2 × 6.022 × 10²³ moles of electrons are transferred.

What is a half-reaction?

A half-reaction represents a single component of the redox reaction, which is a reduction or an oxidation half.

The oxidation half-reaction is:

Ascorbic acid → L-dehydroascorbic acid + 2H⁺ + 2e⁻

The reduction half-reaction is:

N-bromosuccinimide (NBS) + 2H⁺ + 2e⁻ → Succinimide + HBr

During the redox reaction, 2 electrons are transferred, and 1 molecule of NBS reacts with 1 molecule of ascorbic acid that transfers 2 electrons.

So, when 1 mole of NBS reacts with 1 molecule of ascorbic acid than 2 × 6.022 × 10²³ moles of the electron will be transferred.

Therefore, 2 × 6.022 × 10²³ moles of electrons are transferred.

Learn more about half-reaction here:

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