tbsoul9p74mgx
contestada

What is the perimeter, in inches, of the isosceles right triangle shown below, whose hypotenuse is 8 square root of 2 inches long? Answer choices: A. 8
B 8+8 square root2
C. 8+16squareroot2
D. 16
E. 16+8squareroot2

Respuesta :

daphnewong
using the 45 45 90 right triangle theorem to solve this problem, where the isosceles sides are x and the hypotenuse is xrad2

the answer is A, 8

hope this helped!

The perimeter of an isosceles triangle is [tex]16+8\sqrt{2}[/tex].

Given

The hypotenuse of an isosceles right triangle is equal to [tex]8\sqrt{2}[/tex].

What is the perimeter of the isosceles triangle?

The perimeter of an isosceles triangle is the sum of all three sides. an isosceles triangle has 2 equal sides, the perimeter is twice the equal sides plus the different sides.

The other side of the isosceles triangle is;

[tex]\rm 2x=8\sqrt{2}\\\\x=8[/tex]

Therefore,

The perimeter of the isosceles right triangle is;

[tex]\rm Perimeter =2(x)+Other side\\\\Perimeter = 2(8)+8\sqrt{2}\\\\Perimeter = 16+8\sqrt{2}[/tex]

Hence, the perimeter of an isosceles triangle is [tex]16+8\sqrt{2}[/tex].

To know more about perimeter click the link given below.

https://brainly.com/question/283161

Otras preguntas