Respuesta :
The balanced equation for
Ca(OH)2 + H3PO4→ Ca3(PO4)2 + H2O is
3 Ca(OH)2 +2 H3PO4→ Ca3(Po4)2 + 6 H2O
3 moles of Ca(OH)2 reacted with 2 moles of H3PO4 to form 1 mole of Ca3(PO4)2 and 6 moles of H2O
Ca(OH)2 + H3PO4→ Ca3(PO4)2 + H2O is
3 Ca(OH)2 +2 H3PO4→ Ca3(Po4)2 + 6 H2O
3 moles of Ca(OH)2 reacted with 2 moles of H3PO4 to form 1 mole of Ca3(PO4)2 and 6 moles of H2O
Explanation:
A balanced equation is the one which contains equal number of atoms on both reactant and product side.
For example, [tex]Ca(OH)_{2} + H_{3}PO_{4} \rightarrow Ca_{3}(PO_{4})_{2} + H_{2}O[/tex]
Number of atoms on reactant side are as follows.
- Ca = 1
- O = 6
- H = 5
- P = 1
Number of atoms on product side are as follows.
- Ca = 3
- O = 9
- H = 2
- P = 2
Therefore, to balance the chemical equation multiply [tex]Ca(OH)_{2}[/tex] by 3 and multiply [tex]H_{3}PO_{4}[/tex] by 2 on reactant side. Whereas multiply [tex]H_{2}O[/tex] by 6 on product side.
Hence, the balanced chemical equation will be as follows.
[tex]3Ca(OH)_{2} + 2H_{3}PO_{4} \rightarrow Ca_{3}(PO_{4})_{2} + 6H_{2}O[/tex]