Respuesta :
an = 4 + (n - 1)(7)
a1 = 4 + (1-1)*7 = 4
a2 = 4 + (2-1)*7 = 4 + 7
[tex]a_{n} = a_{n-1} +7 [/tex]
7 is common difference of arithmetic sequence.
a1 = 4 + (1-1)*7 = 4
a2 = 4 + (2-1)*7 = 4 + 7
[tex]a_{n} = a_{n-1} +7 [/tex]
7 is common difference of arithmetic sequence.
Answer: [tex]a_n=a_{n-1}+7[/tex]
Step-by-step explanation:
We know that the nth term in Arithmetic sequence is given by :-
[tex]a_n=a+(n-1)d[/tex]..................(1)
Given: A certain arithmetic sequence has the following explicit formula for the nth term:
[tex]a_n=4+(n-1)(7)[/tex].............................(2)
When we compare (1) and (2), we get
[tex]d=7[/tex]
Also, the recursive formula in A.P. can be written as
[tex]a_n=a_{n-1}+d[/tex]
Therefore, The same sequence has the following recursive formula:
[tex]a_n=a_{n-1}+7[/tex]