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contestada

Which value are in the solution set of the compound inequality?

Check all that apply.

4(x+3) ≤ 0 or 1/4x+1>3?

A.-6
B.-3
C.0
D.3
E.8
F.10

Respuesta :

gmany
[tex]4(x+3)\leq0\ \ \ \ |:4\\x+3\leq0\ \ \ |-3\\x\leq-3\\\\\dfrac{1}{4}x+1 \ \textgreater \ 3\ \ \ |-1\\\dfrac{1}{4}x \ \textgreater \ 2\ \ \ \ |\cdot4\\x \ \textgreater \ 8\\\\x\leq-3\ or\ x \ \textgreater \ 8\\\\Answer:\\A.\ -6\\B.\ -3\\F.\ 10[/tex]
Blacklash

Answer:

Option A and B

Step-by-step explanation:

We have 4(x+3) ≤ 0

        x+3 ≤ 0

        x ≤ -3

We also have [tex]\frac{1}{4x+1}>3[/tex]

         [tex]4x+1<\frac{1}{3}\\\\4x<\frac{-2}{3}\\\\x<\frac{-1}{6}[/tex]

We have x ≤ -3 and [tex]x<-\frac{1}{6}[/tex]

Only A and B satisfies both this conditions.

             

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