if dh = 3x -3 and fh = x+7, find the value of x for which defg must be a parallelogram.
a. 7
b. 4
c. 5
d. 2

Answer:
Option c is correct
x = 5
Step-by-step explanation:
Properties of parallelogram:
As per the statement:
In the given DEFG parallelogram,
DH = 3x-3 units
FH=x+7 units
by properties of parallelogram we have;
DH = FH
[tex]3x-3 = x+7[/tex]
Subtract x from both sides we have;
[tex]2x-3 =7[/tex]
Add 3 to both sides we have;
[tex]2x=10[/tex]
Divide both sides by 2 we have;
x = 5
Therefore, the value of x for which DEFG must be a parallelogram is, 5