contestada

The pressure of 5.0 L of gas increases from 1.50 atm to 1240 mm Hg. What is the final volume of the gas, assuming constant temperature?

Respuesta :

manselandy
According to Boyles law, V1P1=V2P2
V1=5L
V2=?
P1=1.5atm
P2=1.632atm
Therefore,
5L*1.5atm=1.632atm*V2
V2=5L*1.5atm/1.632atm
=4.596L

Answer:

4.65 L is the final volume of the gas.

Explanation:

Initial pressure of the gas,[tex]P_1[/tex] = 1.50 atm

Initial volume of the gas,[tex]V_1[/tex] = 5.0 L

Final pressure of the gas ,[tex]P_2[/tex]= 1240 mmHg = 1.612 atm

Final Volume of the gas = [tex]V_2[/tex]

Applying Boyle's law:

[tex]P_1V_1=P_2V_2[/tex] (Constant temperature)

[tex]V_2=\frac{1.50 atm\times 5L}{1.612 atm}=4.65 L[/tex]

4.65 L is the final volume of the gas.

Otras preguntas