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A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.43 m/s2, what is the radius of the circle?
A.0.60 m
B.1.2 m
C.0.36 m
D.0.84 m

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memesbgud
I believe It's A. You really should check other sites like before using your points. Just a little pro tip! Another tip: give me brainliest answer pls.

Answer:

The radius of the circle is 0.60 meters.

Explanation:

It is given that,

Speed of squirrel, v = 0.51 m/s

Centripetal acceleration, [tex]a=0.43\ m/s^2[/tex]  

Let r be the radius of circle. The expression for centripetal acceleration is given by :

[tex]a=\dfrac{v^2}{r}[/tex]

[tex]r=\dfrac{v^2}{a}[/tex]

[tex]r=\dfrac{(0.51\ m/s)^2}{0.43\ m/s^2}[/tex]

r = 0.60 m

So, the radius of the circle is 0.60 meters. Hence, this is the required solution.

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