Answer:
Distance, s = 31.32 meters
Explanation:
It is given that,
Initial velocity of the car, u = 5.82 m/s
Acceleration of the car, [tex]a=2.35\ m/s^2[/tex]
Time taken, t = 3.25 s
We need to find the distance travelled by the car. Let s denotes the distance covered by the car. It can be calculated using the second equation of motion as :
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
[tex]s=5.82\times 3.25+\dfrac{1}{2}\times 2.35\times(3.25)^2[/tex]
s = 31.32 meters
So, the distance travelled by the car is 31.32 meters. Hence, this is the required solution.
