Respuesta :
The answers are 1 and -1.
Assuming the denominator is 3x^2-3, we factor into 3(x^2 - 1) = 3(x-1)(x+1), so the denominator becomes zero for x = -1 and 1. We cannot divide by zero.
Assuming the denominator is 3x^2-3, we factor into 3(x^2 - 1) = 3(x-1)(x+1), so the denominator becomes zero for x = -1 and 1. We cannot divide by zero.