Respuesta :
Answer:
initial value of Relationship 2 is 25
Explanation:
1- Considering Relationship 1:
It has initial value of 5 and rate of change of 1.5
Therefore, its equation would be:
y = 1.5x + 5
Now, we want the output to be 50. This means that:
50 = 1.5x + 5
50 - 5 = 1.5x
45 = 1.5x
x = 30
Therefore, the output will be 50 when the input is 30.
The point is (30,50)
2- Considering Relationship 2:
It has a rate of change of [tex] \frac{5}{6} [/tex] and an initial value of c.
Therefore, the equation of Relationship 2 is:
y = [tex] \frac{5}{6} [/tex]x + c
We have calculated that an output of 50 will occur at an input of 30 for Relationship 1.
We are given that this scenario will also occur is Relationship 2.
Therefore, point (30,50) will satisfy Relationship 2.
We can now solve for c as follows:
y = [tex] \frac{5}{6} [/tex]x + c
50 = [tex] \frac{5}{6} [/tex] * (30) + c
50 = 25 + c
c = 50 - 25
c = 25
This means that Relationship 2 has an initial value of 25
Hope this helps :)
initial value of Relationship 2 is 25
Explanation:
1- Considering Relationship 1:
It has initial value of 5 and rate of change of 1.5
Therefore, its equation would be:
y = 1.5x + 5
Now, we want the output to be 50. This means that:
50 = 1.5x + 5
50 - 5 = 1.5x
45 = 1.5x
x = 30
Therefore, the output will be 50 when the input is 30.
The point is (30,50)
2- Considering Relationship 2:
It has a rate of change of [tex] \frac{5}{6} [/tex] and an initial value of c.
Therefore, the equation of Relationship 2 is:
y = [tex] \frac{5}{6} [/tex]x + c
We have calculated that an output of 50 will occur at an input of 30 for Relationship 1.
We are given that this scenario will also occur is Relationship 2.
Therefore, point (30,50) will satisfy Relationship 2.
We can now solve for c as follows:
y = [tex] \frac{5}{6} [/tex]x + c
50 = [tex] \frac{5}{6} [/tex] * (30) + c
50 = 25 + c
c = 50 - 25
c = 25
This means that Relationship 2 has an initial value of 25
Hope this helps :)
Answer:
Sample Response: The equation of Relationship 1 is y = 3/2x + 5. Substitute 50 for y and solve to find that x = 30. Multiply 30 by 5/6, the rate of change of Relationship 2, to get 25. This means that the initial value would need to be 25 to get to 50 when the input is 30.