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manselandy
The percentage of hydrogen in C7H18 is calculated as follows:
[18/(12*7+1*8)]*100=18%
The amount of hydrogen in 5.2moles is given by:(18/100)*5.2=0.94moles

Answer:

There are 93.6 moles of hydrogen atoms are present in 5.2 moles of [tex]C_7H_{18}[/tex].

Explanation:

We are given:

Moles of [tex]C_7H_{18}[/tex]= 5.2 mol

By Stoichiometry:

in 1 mole of [tex]C_7H_{18}[/tex] there are 18 moles of hydrogen atom.

So, moles of hydrogen atom in 5.2 mol of [tex]C_7H_{18}[/tex]:

[tex]5.2\times 18 mol=93.6 mol[/tex]

There are 93.6 moles of hydrogen atoms are present in 5.2 moles of [tex]C_7H_{18}[/tex].

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