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The position of an object at time t is given by s(t) = -8 - 9t. Find the instantaneous velocity at t = 1 by finding the derivative.

Please show work

Respuesta :

[tex]\bf s(t)=-8-9t\implies \cfrac{ds}{dt}=0-9\implies \left. \cfrac{ds}{dt}=-9 \right|_{t=1}\implies -9[/tex]

meaning the object is slowing down, and regardless of what "t"value is, -9 is just a constant all the way.
vilu1
The answer is -9 units per unit of time

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