[tex]f(x+n)\to\text{translation n units left}\\\\f(x-n)\to\text{translation n units right}\\\\f(x)+n\to\text{translation n units up}\\\\f(x)-n\to\text{translation n units down}\\\\\\f(x)=\left(\dfrac{1}{5}\right)^x\to f(x)+4=\left(\dfrac{1}{5}\right)^x+4\\\\Answer:\ g(x)=\left(\dfrac{1}{5}\right)^x+4[/tex]
