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23-06-2018
Mathematics

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A ball is launched into the sky at 19.5 feet per second from a 54.6 meter tall building. The equation for the ball’s height, h, at time t seconds is h = -3.9t2 + 19.5t + 54.6. When will the ball strike the ground?

Respuesta :

23-06-2018

the ground is at 0, so h=0, so -3.9t^2 + 19.5t + 54.6 = 0. Use the quadratic formula. Hope this helps :D.

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