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Mn2+(aq) + nabio3(s) → bi3+(aq) + mno4−(aq) + na+(aq) how many water molecules are there in the balanced equation (for the reaction balanced with the smallest whole-number coefficients)

Respuesta :


Mn²⁺ + 4H2O -----> MnO4⁻ + 8H⁺ +5e⁻                  /*2
NaBiO3 +6H⁺ +2e⁻ -----> Bi³⁺ + Na⁺ + 3H2O        /*5
2Mn²⁺ + 5 NaBiO3+8H2O+30H⁺ --->  2MnO4⁻ +5Bi³⁺ + 5Na⁺ +16H⁺ +15H2O

2Mn²⁺ + 5 NaBiO3+14H⁺ --->  2MnO4⁻ +5Bi³⁺ + 5Na⁺  +7H2O

There are 7 water molecules in this reaction.
pstnonsonjoku

In balancing redox reaction equation, oxygen atoms are balanced with water.

A redox reaction equation is one in which a specie looses electrons and another specie gains electrons. In other words, in a redox reaction a specie is oxidized and the other specie is reduced.

Given the reaction in the question;

Oxidation half equation is;

2Mn²⁺ + 8H2O ------> 2MnO4⁻ + 16H⁺ + 10e

Reduction half equation:

5 NaBiO3+ + 30 H⁺ + 10e ---------> 5Bi³⁺ + 5Na⁺ + 15H2O

Overall balanced redox reaction equation:

2Mn²⁺ + 5 NaBiO3 + 14H⁺ --->  2MnO4⁻ + 5Bi³⁺ + 5Na⁺  + 7H2O

https://brainly.com/question/13978139

There are seven water molecules in the balanced equation.