jaredlewq
jaredlewq jaredlewq
  • 24-06-2018
  • Mathematics
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[tex] \frac{3-a}{6} -\frac{6-a}{3} =a+1
[/tex]
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mkryukova19 mkryukova19
  • 24-06-2018
[tex] \frac{3-a}{6} -\frac{6-a}{3} =a+1; \\ \\ \frac{3-a}{6} -\frac{2(6-a)}{3*2} =a+1 \\ \\ \frac{3-a-12+2a}{6} =a+1 \\ \\ 6*\frac{a-9}{6} = 6*(a+1) \\ \\ a-9 = 6a+6 \\ \\ 5a= -15 \\ \\ a=-3[/tex]
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