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A die is rolled twice. what is the probability of getting either a multiple of 3 on the first roll or a total of 7 for both rolls?

Respuesta :

P(multiple of 3) = 2/6 = 1/3
P(total of 7) = 6/36 = 1/6
1/3 + 1/6 = 1/2

Hopefully this helped.

The probability of getting either a multiple of 3 on the first roll or a total of 7 for both rolls is 1/9.

What is probability?

Probability is the measure of the likelihood of an occurrence.

For the first roll:

Sample space = {3,6) i.e. 2

Total outcomes ={1, 2, 3, 4, 5, 6} i.e. 6

So the probability of getting a multiple of 3 the first time = 2/6 = 1/3

For the second roll:

In order to get a total of 7 one needs 4 or 1 because in the first roll if we get 3 we need 4 to make 7 and if we get 6 we need 1 to make 7.

Sample space ={4,1} i.e. 2

Total outcomes ={1, 2, 3, 4, 5, 6} i.e. 6

So the probability of getting 4 or 1 = 2/6 =1/3

Total probability = 1/3 * 1/3 = 1/9

Hence, the probability of getting either a multiple of 3 on the first roll or a total of 7 for both rolls is 1/9.

To get more about probability visit:

https://brainly.com/question/24756209