Answer:
[tex]m_{Si}=5.04gSi[/tex]
Explanation:
Hello,
In this case, we use the Avogadro's number and the atomic mass of silicon to find the grams that are present in that amount of atoms by using the following atoms-mole-mass relationship:
[tex]m_{Si}=1.08x10^{23}atomsSi*\frac{1molSi}{6.022x10^{23}atomsSi} *\frac{28.1gSi}{1molSi} \\\\m_{Si}=5.04gSi[/tex]
That is why in mole of silicon there are 6.022x10^(23) atoms of silicon as well as 28.1 g of silicon.
Best regards.
