One positive integer is 3 units more than another. When the reciprocal of the larger is subtracted from twice the reciprocal of the smaller, the result is 2/9. Find the two positive integers.
x=y+3 (2/y)-(1/x)=2/9 Use systems of equations, plug x-3 for y (2/x-3)-(1/x)=2/9 y= 6, -9/2 Therefore, x = 9, -3/2 But it's positive, so the integers are 6 and 9
