Suppose that the functions and are defined for all real numbers as follows. r(x)=3x^(2) s(x)=2x write the expressions for (r-s)(x) and (r+s)(x) and evaluate (r*s)(-1).

Respuesta :

The expression for (r-s)(x) is found by subtracting s from r.  That difference is [tex]3 x^{2} -2x[/tex].  The expression for (r+s)(x) is found by adding them, which is [tex]3 x^{2} +2x[/tex].  Now we are told to evaluate (r*s)(x) which means they want us to multiply those and state the "new" expression that results.  [tex](3 x^{2} )(2x)=6x^3[/tex].  There you go!