Answer: (1,2)
Step-by-step explanation:
The given system of linear equations :-
[tex]8x+4y=16 \\7y=15-x[/tex] which can be written as ,
[tex]2x+y=4..........(1) \text{[Divide both sides by 2]}\\7y+x=15................(2)\text{[Add x on both sides]}[/tex]
Now, Multiply 2 on both sides of equation (2), we get
[tex]14y+2x=30.........(3)[/tex]
Subtract equation (1) from equation (3) , we get
[tex]13y=26\\\\\Rightarrow\ y=2[/tex]
Put y= 2 in (1), we get
[tex]2x+2=4\\\\\Rightarrow\ 2x=2\\\\\Rightarrow\ x=1[/tex]
Hence, the solution to the given system is (1,2).
