We can solve the problem by using the ideal gas equation: [tex]pV=nRT[/tex] where p is the pressure of the gas V is the volume of the gas n is the number of moles of the gas R is the gas constant T is the absolute temperature of the gas
For the gas in our problem, we have: [tex]p=100000 Pa[/tex] [tex]R=8.314 J mol^{-1} K^{-1}[/tex] [tex]T=300 K[/tex] [tex]n=100[/tex]
If we rearrange the equation and we put these numbers into it, we find the volume of the gas: [tex]V= \frac{nRT}{p}= \frac{(100)(8.314)(300)}{100000}=2.49 m^3 [/tex]
