Respuesta :

Simply plug in x = 0

f(x) = x^2 - 5
f(0) = 0^2 - 5
f(0) = -5

Answer: -5
isyllus

Answer:

The value of limit is -5

Step-by-step explanation:

Given: [tex]\lim_{x\rightarrow 0}x^2-5[/tex]

We need to find limit by direct substitution.

"quantity x squared minus five" : x²-5

We will put x=0 into function.

[tex]L=\lim_{x\rightarrow 0}x^2-5[/tex]

[tex]L=0^2-5[/tex]

[tex]L=0-5[/tex]

[tex]L=-5[/tex]

Hence, The value of limit is -5

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