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How does the graph of y=(√x)+2 compare to the graph of the parent square root function? The graph is a horizontal shift of the parent function 2 units right. The graph is a horizontal shift of the parent function 2 units left. The graph is a vertical shift of the parent function 2 units up. The graph is a vertical shift of the parent function 2 units down.

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The parent square root function has a starting point at the origin.  In standard form that would look like this: [tex]y= \sqrt{x-0}+0 [/tex], where the number inside the radical with the x indicates side to side movement, and the number following either a + or a - indicates up or down movement.  Our movement is up or down, since there is no number with the x under the radical.  Because that is +2, our parent graph moves up to units from an original starting point of (0, 0) to a new one of (0, 2).  Summary:  the parent graph moves up 2 units, third choice above
yankeesthe2

Answer:

The parent square root function has a starting point at the origin.  In standard form that would look like this: , where the number inside the radical with the x indicates side to side movement, and the number following either a + or a - indicates up or down movement.  Our movement is up or down, since there is no number with the x under the radical.  Because that is +2, our parent graph moves up to units from an original starting point of (0, 0) to a new one of (0, 2).  Summary:  the parent graph moves up 2 units, third choice above

Step-by-step explanation:

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