Will give brainliest. 50 points.. find the surface area of the cone in terms of pi please help.

so, the diameter of the cone is 12 cm, therefore its radius is 6 cm, keeping in mind its slant height is 18 cm.
[tex] \bf \textit{surface area of a cone}\\\\
SA=\pi r\stackrel{slant~height}{\sqrt{r^2+h^2}}+\pi r^2~~
\begin{cases}
r=radius\\
-------\\
\qquad ~~ ~~ ~ r=6\\
\sqrt{r^2+h^2}=18
\end{cases}
\\\\\\
SA=\pi (6)(18)+\pi (6)^2\implies SA=108\pi +36\pi \implies SA=144\pi [/tex]
The base area is given by
... A = π·r²
For a radius of 6 cm, this is
... A = π·(6 cm)² = 36π cm²
The lateral area is given by
... A = (1/2)C·s = (π/2)d·s
where C is the circumference of the base, d is the base diameter, and s is the slant height.
For a base diameter of 12 cm, this is
... A = (π/2)·(12 cm)·(18 cm) = 108π cm²
Then the total surface area of the cone is
... surface area = base area + lateral area
... surface area = (36π cm²) + (108π cm²)
... surface area = 144 cm²