Respuesta :
First of all, let's count how many events compose our sample space: since we are rolling two dice, and each of them has six sides, the sample space has 36 possible events, given by all couples [tex] (x,y) [/tex], with [tex] x,y \in \{1,2,3,4,5,6\} [/tex]
Then, we observe that none of the die can give 4 or more, otherwise the sum of the two dice would be at least 5.
So, we have the following possible outcomes:
Red die gives 1, green die gives 3
Both dice give 2
Red die gives 3, green die gives 1.
These are three events out of the 36 possible events, so their probability is
[tex] \cfrac{3}{36} = \cfrac{1}{12} [/tex]
The probability that the sum of the numbers is less than 4 is 1/12 and this can be determined by using the given data.
Given :
Suppose that a red die and a green die are tossed and the numbers on the sides that face upward are observed.
The following steps can be used in order to determine the probability that the sum of the numbers is less than 4:
Step 1 - The sample space is given by:
[tex]=6^2 = 36[/tex]
Step 2 - According to the given data, the sum of the numbers should be less than 4. So, it can be concluded that none of the dies can give 3 or more than 3.
Step 3 - Therefore, the probability that the sum of the numbers is less than 4 is:
[tex]\rm P = \dfrac{3}{36}[/tex]
[tex]\rm P=\dfrac{1}{12}[/tex]
So, the probability that the sum of the numbers is less than 4 is 1/12.
For more information, refer to the link given below:
https://brainly.com/question/23044118
