Respuesta :
Given: Mean temperature μ = 24 , standard deviation σ =4
The lower and upper bound for temperature within one standard deviation of the mean is given by,
Lower bound = μ - σ = 24 - 4
Lower bound = 20
Upper bound = μ + σ = 24+ 4
Upper bound = 28
The temperature value between (20, 28) is said to be within one standard deviation of the mean.
From given option 27° lies in between (20°, 28°), hence 27° is the temperature value that is within one standard deviation of mean.
27 is the standard value.
Standard deviation
A quantity is expressed by how much the member of the group differs from the mean value.
Given
Mean ([tex]\mu[/tex]) = 24
Standard deviation ([tex]\sigma[/tex]) = 4
How to calculate the standard deviation?
Lowered bound = [tex]\mu - \sigma[/tex]
Lowered bound = 24 - 4
Lowered bound = 20
Upper bound = [tex]\mu + \sigma[/tex]
Upper bound = 24 + 4
Upper bound = 28
The temperature value between (20, 28) is said to be within one standard deviation of the mean.
Thus, 27 lies between (20, 28).
Hence, 27 is the standard value.
More about the standard deviation link is given below.
https://brainly.com/question/12402189
