Respuesta :
Step 1:
In a sample of 380 randomly selected reservations, 19 were no-shows.
Step 2:
Proportion of no shows p<0.06.
Step 3:
Test Value
z(19/380)=0.05
Step 4:
Test statistics
a) 0.05-1.124=-1.074
b) 0.05-(-1.943) = 0.05+1.943=1.993
c)0.05-(-0.821)=0.05+0.821=0.871
d)0.05 - 0.222 = - 0.172
e)0.05 -(-1.571) = 0.05+1.571 = 1.621
The above data clearly mentions the test statistics associated with the given samples.
Answer: -0.821
Step-by-step explanation:
The test statistic for population proportion (p) is given by :-
[tex]z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}[/tex]
Given : An airline claims that the proportion of no-shows for passengers who booked on its flights is less than 0.06.
Sample size = 380
The proportion that there were no-shows = [tex]\dfrac{19}{380}=0.05[/tex]
The test statistic for population proportion (p) is given by :-
[tex]z=\dfrac{0.05-0.06}{\sqrt{\dfrac{0.06(1-0.06)}{380}}}\\\\=0.8208281581\approx-0.821[/tex]
Hence, the test statistic associated with this sample = -0.821