first reflect across x=-3
you get (-6,0)
then reflect across y=4
we have (-6,8)
x=-6
y=8
Answer:
The reflection image would be (-6,8).
Step-by-step explanation:
Since, when a point is reflected across a line x = p
Then, the rule of reflection is,
[tex](x,y)\rightarrow (2p-x, y)[/tex]
While, across a line y = p,
The rule of reflection is,
[tex](x,y)\rightarrow (x, 2p-y)[/tex]
Thus, when (0,0) is reflected across x = -3,
[tex](0,0)\rightarrow (2(-3)-0,0)[/tex]
The image after reflection is (-6,0),
Again when (-6,0) is reflected across y = 4,
[tex](-6,0)\rightarrow (-6, 2(4)-0)[/tex]
Hence, the resultant image after both reflections would be (-6,8).
