Use ΔABC to answer the question that follows:
Given: ΔABC

Prove: The three medians of ΔABC intersect at a common point.

When written in the correct order, the two-column proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point:


Statements Justifications
Point F is a midpoint of Line segment AB Point E is a midpoint of Line segment AC Draw Line segment BE Draw Line segment FC by Construction
Point G is the point of intersection between Line segment BE and Line segment FC Intersecting Lines Postulate
Draw Line segment AG by Construction
Point D is the point of intersection between Line segment AG and Line segment BC Intersecting Lines Postulate
Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH by Construction
I BGCH is a parallelogram Properties of a Parallelogram (opposite sides are parallel)
II Line segment BD ≅ Line segment DC Properties of a Parallelogram (diagonals bisect each other)
III Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC Substitution
IV Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC Midsegment Theorem
Line segment AD is a median Definition of a Median
Which is the most logical order of statements and justifications I, II, III, and IV to complete the proof?
III, IV, II, I
IV, III, I, II
III, IV, I, II
IV, III, II, I

Respuesta :

DeanR

Let's try to render the first part of the proof a bit more legibly.


Point F is a midpoint of Line segment AB

Point E is a midpoint of Line segment AC

Draw Line segment BE

Draw Line segment FC by Construction

Point G is the point of intersection between Line segment BE and Line segment FC Intersecting Lines Postulate

Draw Line segment AG by Construction

Point D is the point of intersection between Line segment AG and Line segment BC Intersecting Lines Postulate

Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH by Construction


OK, now we continue. We need to prove some parallel lines; statement 4 lets us do so.


IV Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC -------- Midsegment Theorem


Now that we've shown some segments parallel we extend that to collinear segments.


III Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC -------- Substitution


We have enough parallel lines to prove a parallelogram


I BGCH is a parallelogram -------- Properties of a Parallelogram (opposite sides are parallel)


Now we draw conclusions from that.


II Line segment BD ≅ Line segment DC -------- Properties of a Parallelogram (diagonals bisect each other)


Answer: IV III I II, second choice


Answer:

the second option

Step-by-step explanation: