Respuesta :

[tex] x^2 +3x-18=0\\
x^2-3x+6x-18=0\\
x(x-3)+6(x-3)=0\\
(x+6)(x-3)=0\\
x=-6 \vee x=3 [/tex]

Your solutions would be x = -6 or x = 3.


To find the solutions of this equation you must first factor it by finding factors of -18 that have a difference of 3. This gives you:


(x + 6)(x - 3) = 0


If you set each bracket equal to 0, you can solve for x by either adding 3 or subtracting 6 and get x equal to -6 or 3.


I hope this helps!