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If two cards are randomly chosen from a standard deck, what is the probability that a 6 is chosen, NOT replaced, and another 6 is chosen?
A. 2/36
B. 16/2652
C. 16/2704
D. 12/2652

Respuesta :

altavistard

The probability of choosing a 6 without replacement is different from that of choosing a 6 with replacement.


First draw: P(6) = 4/52 = 1/4 (there are 4 6's in the full deck)

Second draw: P(6|6 was previously chosen and not replaced) = 4/51 (there are 3-6's left among 51 cards)

P(a 6 is chosen, NOT replaced, and another 6 is chosen) =


(1/4)(3/51) = 1/68

konrad509

[tex]|\Omega|=52\cdot51=2652\\|A|=4\cdot3=12\\\\P(A)=\dfrac{12}{2652}[/tex]

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