Respuesta :
Concentration (m) signify 'molality'
Concentration (M) signify 'Molarity'
Formula for molality (m) = [tex] \frac{Moles of solute}{Mass of solvent in Kg} [/tex]
In the question denisty of solute is not given so we can calculate concentration (M) that is 'Molarity'
Molarity (M) = [tex] \frac{Moles of solute}{Volume of solution in L} [/tex]
Moles of solute CH3OH = Given grams / Molar mass of CH3OH
Given grams of CH3OH = 12.9 g and molar mass = 32.0 g/mol
Moles of solute CH3OH = [tex]12.9 g\times \frac{1mol}{32.0g}[/tex]
Moles of solute CH3OH = 0.403 mol
Volume of solution = 230 mL , we need to convert 230 mL to 'L'
Volume = [tex] 230 mL\times \frac{1 L}{1000 mL} [/tex]
Volume = 0.23 L
Molarity (M) = [tex] \frac{0.403mol}{0.23L} [/tex]
Concentration (M) = 1.75 mol / L or 1.75 M
