Given: Mean μ = 61.2 and standard deviation σ =21.4
The Z score of the value x=45 is given by
Z = [tex] \frac{x - mean}{standard deviation} [/tex]
Z = [tex] \frac{45 - 61.2 }{21.4} [/tex]
Z = [tex] \frac{-16.2}{21.4} [/tex]
Z = -0.757
The z-score value for 45 rounded to nearest tenth is -0.8
