`stackrel(harr)(DG)` and `stackrel(harr)(EG)` are tangent to circle C and circle F. The points of tangency are A, B, D, and E. If m`/_DFE` = 140°, what is m`/_ACB`?

Respuesta :

General Idea:

Sum of angles subtended at the centre and point of contact by tangents down from an external point is supplementary (180°).

Applying the concept:

Considering the point of contact of two tangents of large circle, we can write

[tex] \angle DFE+\angle DGE=180 [/tex]

We are given [tex] \angle DFE=140 [/tex], so the equation will become

[tex] 140+\angle DGE=180 [/tex] {Subtracting 140 on both sides}

[tex] 140+\angle DGE -140 = 180 - 140\\ \\ \angle DGE = 40 [/tex]

Considering the point of contact of two tangents of small circle, we can write

[tex] \angle ACB + \angle AGB = 180\\ \\ Note: \angle AGB = \angle DGE = 40\\ \\ \angle ACB + 40 = 180 [/tex]

Subtracting 40 on both sides, we get...

[tex] \angle ACB +40 - 40 = 180 - 40\\ \\ \angle ACB = 140 [/tex]

Conclusion:

[tex] /angle ACB = 40 [/tex]

Ver imagen berno

The correct answer is B. 140