[tex](x-5)^2=81\to x-5=\pm\sqrt{81}\ \ \ |+5\\\\x=5\pm\sqrt{81}[/tex]
Answer: 5 ± √(81)
Answer:
Option 2nd is correct
[tex]5 \pm \sqrt{81}[/tex]
Step-by-step explanation:
Given the equation:
[tex](x-5)^2 = 81[/tex]
Taking square root both sides we have;
[tex]\sqrt{(x-5)^2}= \pm \sqrt{2}[/tex]
Using the exponent rule:
[tex]\sqrt[n]{x^n}=x[/tex]
then;
[tex]x-5 = \pm \sqrt{81}[/tex]
Add 5 to both sides we have;
[tex]x-5+5= 5 \pm \sqrt{81}[/tex]
Simplify:
[tex]x = 5 \pm \sqrt{81}[/tex]
Therefore, the following expressions represents the solutions to the given equation is, [tex]5 \pm \sqrt{81}[/tex]
