one+four+three=eight pens.
Two pens are selected without replacement.
Need probability of selecting two black pens.
Probability of selecting first black pen is four out of eight, 4/8
Probability of selecting second black pen is three remaining black pens out of the remaining 7 pens = 3/7
Probability of both events happening is the product of the two probabilities, according to the multiplication rule.
Therefore probability of selecting two black pens out of the initial eight pens
=(4/8)(3/7)=3/14=0.2143 (to the ten-thousandth).
Rounding to the hundredth will give you the required answer.
