Answer : The correct option is, (B) Tetrahedral compound
Explanation :
Formula used:
[tex]\text{Number of electrons}=\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
First we have to determine the hybridization of the [tex]CH_4[/tex] molecule.
[tex]\text{Number of electrons}=\frac{1}{2}\times [4+4]=4[/tex]
The number of electrons are 4 and there is no lone pairs present on the central carbon atom that means the hybridization will be [tex]sp^3[/tex] and the electronic geometry of the molecule will be tetrahedral.
Hence, the shape of the given compound [tex]CH_4[/tex] is, tetrahedral.
