Please help! 11 pts.
Triangle ABC is formed by the three squares X, Y, and Z: A right triangle ABC is shown. On the side AB of this triangle is a square. Inside the square is written Square X, and below it and inside the square is written Area equal to 25 square units. On the side BC of this triangle is another square. Inside the square is written Square Y, and below it and inside the square is written Area equals 144 square units. On the side AC of this triangle is another square. Inside the square is written Square Z, and below it and inside the square is written Area equal to 169 square units. Which statement best explains the relationship between the sides of triangle ABC?
Multiple Choice:
AB + BC = AC, because 25 + 144 = 169
(AB)2 + (BC)2 = (AC)2, because 132 + 52 = 122
AB + BC = AC, because 132 + 52 = 122
(AB)2 + (BC)2 = (AC)2, because 25 + 144 = 169

Please help 11 pts Triangle ABC is formed by the three squares X Y and Z A right triangle ABC is shown On the side AB of this triangle is a square Inside the sq class=

Respuesta :

The Pythagorean theorem formula for a triangle is A^2 + B^2 = C^2 where A and B are the sides and C is the hypotenuse.

The sides of the triangle shown are AB and BC and the hypotenuse is AC,

so the correct answer would be:

(AB)2 + (BC)2 = (AC)2, because 25 + 144 = 169

We can see that right triangle ABC has

1) leg AB, that is a side of the square X, side of the square X, AB= √25,

2) leg BC that is a side of the square Y, side of the square Y, BC = √144,

3) hypotenuse AC that is a side of the square Z, side of the square Z, AC = √169.

For right triangle we can use Pythagorean Theorem.

(leg1)² + (leg2)² = hypotenuse²

(AB)² + (BC)² = (AC)²

(√25)² + (√144)² = (√169)²

25 +144=169.

So, we have (AB)² + (BC)² = (AC)² and 25 +144=169.

Answer is D. (AB)² + (BC)² = (AC)² because 25 +144=169.