The given inequality is ,
[tex] \frac{x}{12} +3\leq 7 [/tex].
To solve the inequality we need to isolate x. So, first step is to remove +3 from the left side. Hence, subtract 3 from each sides. Therefore,
[tex] \frac{x}{12} +3-3\leq 7-3 [/tex]
[tex] \frac{x}{12}\leq 4 [/tex]
[tex] \frac{x}{12}*12\leq 4*12 [/tex] Multiply 12 from each sides to isolate x.
[tex] x\leq 48 [/tex]
So, the solution of the given inequality is [tex] x\leq 48 [/tex].