A running track in the shape of an oval is shown. The ends of the track form semicircles.What is the perimeter of the inside of the track? (π = 3.14) 260.00 m 347.92 m 372.00 m 435.84 m

A running track in the shape of an oval is shown The ends of the track form semicirclesWhat is the perimeter of the inside of the track π 314 26000 m 34792 m 37 class=

Respuesta :

Two semi circles would equal one circle.

The perimeter of a circle is PI x diameter.

The diameter of the circle is shown as 56 m

The perimeter of the 2 ends = 56 x 3.14 = 175.84

The length of the inside of the track is given as 130 m, and there are 2 sides so 130 + 130 = 260 m.

Total perimeter = 260 + 175.84 = 435.84 m.

The perimeter of the inside of the track is 435.84 m.

Given

A running track in the shape of an oval is shown.

The ends of the track form semicircles.

The diameter of the shape is 56.

What is the circumference of a circle?

The circumference of the circle is equal to two times of radius.

The perimeter of the circle is;

[tex]\rm Perimeter=2\pi r\\\\Perimeter = 2\pi \times \dfrac{diameter}{2}\\\\Perimeter = \pi \times diameter\\\\Perimeter= \pi \times 56\\\\Perimeter= 3.14 \times 56\\\\Perimeter= 175.84[/tex]

The length of the inside of the track is given as 130 m, and there are 2 sides is;

= 130 + 130 = 260m

Therefore,

The perimeter of the inside of the track is;

The perimeter of the track = length inside track + perimeter of the circle.

The perimeter of the track = 260 + 175.84

The perimeter of the track = 435.84 m

Hence, the perimeter of the inside of the track is 435.84 m.

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