48a2 + 32a2 + 16a by 4a?

(48a^3 + 32a^2 + 16a) / 4a = ?
48a^3 / 4a = 12a^2
32a^2 / 4a = 8a
16a / 4a = 4
so
(48a^3 + 32a^2 + 16a) / 4a = 12a^2 + 8a + 4
Answer is D. 12a^2 + 8a + 4
In a similar way to how we distribute multiplication across addition (ex: 2 x (3 + 2) = 2 x 3 + 2 x 2) we can distribute this division, too. We divide each term individually by 4a, and then add them back together again:
[tex] 48a^3\div4a=12a^2 \\
32a^2\div4a=8a\\
16a\div4a=4 [/tex]
Adding all those divided terms together, we get the expression 12a² + 8a + 4, which is D.