To solve this problem you must apply the proccedure shown below;
1. You have the following equation given in the problem above:
[tex] \frac{1}{36} = 6^{(x-3)} [/tex]
2. You must apply logarithm at both sides of the equation, then, you need to apply the logaritms properties to solve for [tex] x [/tex] and calculate its value, as following:
[tex] log(\frac{1}{36} )=log6^{(x-3)} \\ log(\frac{1}{36} )=(x-3)log(6)\\ x=[\frac{log(\frac{1}{36} )}{log(6)} ]-3\\ x=1 [/tex]
Therefore, the answer is: [tex] x=1 [/tex]
