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Chase got a lab report back with a "-5.0% error" written in red on it. He had determined the boiling point of an unknown liquid to be 45°C. What is the correct boiling point of the unknown liquid?

Chase got a lab report back with a 50 error written in red on it He had determined the boiling point of an unknown liquid to be 45C What is the correct boiling class=

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Answer: The boiling point of the liquid is 47.368°C.

Explanation: The percent error is a tool used to determine the precision of the calculations.

[tex]\%\text{ error}=\frac{(\text{Experimental Value - Theoretical Value})}{\text{Theoretical Value}}\times100[/tex]

Here, we need to calculate the Theoretical Value,

Experimental value = 45°C

% error = -5.0%

Let theoretical value be "x"

[tex]-5.0=\frac{(45-x)}{x}\times100[/tex]

[tex]-5x=(45-x)\times 100\\-5x=4500-100x\\95x=4500\\x=47.368\°C[/tex]

The correct boiling point of the unknown liquid is 47.368°C

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