Answer:
(x,y)=(2,-6)
Step-by-step explanation:
we are given system of equations as
[tex]x=\frac{1}{2}y+5[/tex]
[tex]2x+3y=−14[/tex]
now, we can plug first equation into second equation
[tex]2(\frac{1}{2}y+5)+3y=−14[/tex]
now, we can solve for y
[tex]2\cdot \frac{1}{2}y+2\cdot \:5+3y=-14[/tex]
[tex]4y+10=-14[/tex]
Subtract both sides by 10
[tex]4y=-24[/tex]
divide both sides by 4
[tex]y=-6[/tex]
now, we can plug back y=-6 and find x
[tex]x=\frac{1}{2}\times-6+5[/tex]
[tex]x=-3+5[/tex]
[tex]x=2[/tex]
so, we get solution as
(x,y)=(2,-6)
