[tex] f(x)=\dfrac{4}{x}\qquad\qquad\qquad g(x)=\dfrac{4}{x}\\\\\\\\f(g(x))=f(\frac{4}{x})=\dfrac{4}{\frac{4}{x}}=4\cdot\dfrac{x}{4}=\boxed{x}\\\\\\\\
g(f(x))=g(\frac{4}{x})=\dfrac{4}{\frac{4}{x}}=4\cdot\dfrac{x}{4}=\boxed{x} [/tex]
so f and g are inverses.