[tex] \text{Consider the equation}\\ \\ B=\frac{8}{5}(j-33)\\ \\ \text{so in order to solve it for j, first we mutliply both sides by 5 to get rid}\\ \text{of the 5 from the right denominator. so we get}\\ \\ 5B=5\times \frac{8}{5}(j-33)\\ \\ \Rightarrow 5B=8(j-33)\\ \\ \text{now to get rid of 8, divide both sides by 8, so we get}\\ \\ \frac{5B}{8}=\frac{8(j-33)}{8} [/tex]
[tex] \Rightarrow \frac{5B}{8}=(j-33)\\ \\ \text{now we add 33 both sides to get}\\ \\ \frac{5B}{8}+33=j-33+33\\ \\ \Rightarrow \frac{5B}{8}+33=j\\ \\ \text{so the equation for j is}\\ \\ j=\frac{5B}{8}+33
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