Given profit function [tex] y=-100(x-1.75)^2+300 [/tex] where y gives profit when x is the price of a load of bread in dollars.
Ans(a):
Domain means what values of x can be taken for given function so that function is defined.
Since x represents the price of a load of bread in dollars which can't be negative in practice.
So domain will be all positive real numbers. We can also write x>0
x can't be negative.
Ans(b):
Plug x=2 into given equation.
[tex] y=-100(2-1.75)^2+300=-100(0.25)^2+300=-100(0.0625)+300=-6.25+300=293.75 [/tex]
Hence profit when load of bread is sold at $2 is $293.75.
Ans(c):
Given function is quadratic and we know that maximum occurs at the vertex of quadratic function.
compare given quadratic equation with [tex] y=a(x-h)^2+k [/tex], we get:
h=1.75 and k=300
For quadratic equation [tex] y=a(x-h)^2+k [/tex], vertex is given by (h,k)
Hence vertex for given equation is (1.75,300)
Hence bakery should change selling price to $1.75 in order to get maximum profit.
Ans(d):
Maximum profit as per above calculation is $300.