First of all, we can find the acceleration of the rocket, which is given by:
[tex] a=\frac{v-u}{t} [/tex]
where v is the final velocity of the rocket, u its initial speed, and t the time interval. Plugging in the data of the problem, we find
[tex] a=\frac{132 m/s-88 m/s}{15 s}=2.93 m/s^2 [/tex]
And now we can find the displacement of the rocket using the following equation:
[tex] S=ut+\frac{1}{2}at^2=(88 m/s)(15 s)+\frac{1}{2}(2.93 m/s^2)(15 s)^2 =1649.6 m [/tex]
